Specific Heat Problem Example
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How much heat is lost when a solid Al ingot
with a mass of 4110g cools from 933 K to
298 K?
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Q = m c
Δ
T
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Q = 4110g (933K-298K) (.903 J/g
.
K)=
2,360,000 J.
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Remember, the surroundings will gain an
equal amount of heat.
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